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-5x^2-27x-10=0
a = -5; b = -27; c = -10;
Δ = b2-4ac
Δ = -272-4·(-5)·(-10)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-23}{2*-5}=\frac{4}{-10} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+23}{2*-5}=\frac{50}{-10} =-5 $
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